[Phpmyadmin-devel] Re: small bug in 2.2.0rc1 (user_details.php3)
Loïc
loic-div at ifrance.com
Fri Jul 6 14:45:38 CEST 2001
Once upon a time, Loïc wrote:
>> Please try to replace line 35 by:
>> table_grants($row['host'], $row['user'], $dbcheck);
And Armel replied:
>Ok. Yes, it works.
>But now :
>Parse error: parse error in
>/usr/local/apache/htdocs/armel/phpMyAdmin-devel/user_details.php3 on line
521
Same problem. I do not have access to CVS from here, if
someone can do it...
Here is the list of the changes.
Replace line 521 by:
$checked = ($row[$priv_priv] == "Y") ? "checked" : "";
and line 610 by:
<?php if ($row['Password'] != "") { ?>
and lines 686-699 by:
if ($row['Select_priv'] == "Y") $strPriv .= "Select ";
if ($row['Insert_priv'] == "Y") $strPriv .= "Insert ";
if ($row['Update_priv'] == "Y") $strPriv .= "Update ";
if ($row['Delete_priv'] == "Y") $strPriv .= "Delete ";
if ($row['Create_priv'] == "Y") $strPriv .= "Create ";
if ($row['Drop_priv'] == "Y") $strPriv .= "Drop ";
if ($row['Reload_priv'] == "Y") $strPriv .= "Reload ";
if ($row['Shutdown_priv'] == "Y") $strPriv .= "Shutdown ";
if ($row['Process_priv'] == "Y") $strPriv .= "Process ";
if ($row['File_priv'] == "Y") $strPriv .= "File ";
if ($row['Grant_priv'] == "Y") $strPriv .= "Grant ";
if ($row['References_priv'] == "Y") $strPriv .= "References ";
if ($row['Index_priv'] == "Y") $strPriv .= "Index ";
if ($row['Alter_priv'] == "Y") $strPriv .= "Alter ";
and line 708 by
$edit_url .= "&edit=1&host=" . urlencode($row['Host']) . "&user=" .
urlencode($row['User']);
and line 712 by:
$delete_url .= "&delete=1&confirm=1&delete_host=" . urlencode($row['Host'])
. "&delete_user=" . urlencode($row['User']);
and line 717 by
$check_url .= "&grants=1&host=" . urlencode($row['Host']) . "&user=" .
urlencode($row['User']);
and line 719 by
# $check_result = mysql_query("SHOW GRANTS FOR '" . $row['User'] .
"'@'" . $row['Host'] ."'");
and line 728-730 by
<td><?php echo $row['Host']; ?></td>
<td><?php echo $row['User'] ? "<b>" . $row['User']. "</b>" : "<font
color=\"#FF0000\">$strAny</font>"; ?></td>
<td><?php echo $row['Password'] ? $strYes : "<font
color=\"#FF0000\">$strNo</font>"; ?></td>
Cheers,
Loïc
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