[phpMyAdmin Developers] What is wrong ?

lavercq jc.clariond at gmail.com
Wed May 30 00:17:38 CEST 2018


I have a problem between MySQL and PHP...
When I try this in MySQL :
SELECT * FROM SJH JOIN sjhliaison ON ( SJH.ID = sjhliaison.PID AND
sjhliaison.Tlid ='$Tid' ) WHERE sjhFrancais LIKE  '$item%'

puting '28' for $Tid and 'osier' in place of $item :
SELECT  *  FROM SJH JOIN sjhliaison ON ( SJH.ID = sjhliaison.PID AND
sjhliaison.Tlid = '28' )  WHERE sjhFrancais LIKE 'osier%';

‚ÄčI have 3 answers  :
‚ÄčAffichage des enregistrements 0 - 2 (3 total, Traitement en 0.0147 sec.)

But when i try this with php : *Aucun mot ne correspond !*
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