[phpMyAdmin Developers] What is wrong ?
lavercq
jc.clariond at gmail.com
Wed May 30 00:17:38 CEST 2018
I have a problem between MySQL and PHP...
When I try this in MySQL :
SELECT * FROM SJH JOIN sjhliaison ON ( SJH.ID = sjhliaison.PID AND
sjhliaison.Tlid ='$Tid' ) WHERE sjhFrancais LIKE '$item%'
puting '28' for $Tid and 'osier' in place of $item :
SELECT * FROM SJH JOIN sjhliaison ON ( SJH.ID = sjhliaison.PID AND
sjhliaison.Tlid = '28' ) WHERE sjhFrancais LIKE 'osier%';
I have 3 answers :
Affichage des enregistrements 0 - 2 (3 total, Traitement en 0.0147 sec.)
But when i try this with php : *Aucun mot ne correspond !*
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