11 Apr
2006
11 Apr
'06
9:50 a.m.
Hi
On Tue, 11 Apr 2006 15:27:39 +0200
Sebastian Mendel <lists(a)sebastianmendel.de> wrote:
Michal Čihař schrieb:
and variable not in _ENV is not returned by getenv.
Just try this code:
foreach($_SERVER as $key => $val) {
if ($val != getenv($key)) {
echo "$key differs from _SERVER\n";
echo "$key = $val / " . getenv($key) . "\n";
}
}
foreach($_ENV as $key => $val) {
if ($val != getenv($key)) {
echo "$key differs from _ENV\n";
echo "$key = $val / " . getenv($key) . "\n";
}
}
Most likely some variables from _SERVER are not available throught
getenv:
PHP_SELF differs from _SERVER
PHP_SELF = test.php /
SCRIPT_NAME differs from _SERVER
SCRIPT_NAME = test.php /
SCRIPT_FILENAME differs from _SERVER
SCRIPT_FILENAME = test.php /
PATH_TRANSLATED differs from _SERVER
PATH_TRANSLATED = test.php /
REQUEST_TIME differs from _SERVER
REQUEST_TIME = 1144763136 /
--
Michal Čihař | http://cihar.com
On Tue, 11 Apr 2006 14:45:28 +0200
Sebastian Mendel <lists(a)sebastianmendel.de> wrote:
What do you exactly mean with 'server' and 'environment'?
no $_SERVER variable is in $_ENV the reason why i dropped check for $_SERVER/$_ENV
was i thoguth there is
no need for this function-call-overhead for checking this arrays - as
normally getenv() should always work.
getenv can not work when something is _only_ a server variable but not
in environment.