-----Original Message----- From: Marc Delisle [mailto:DelislMa@CollegeSherbrooke.qc.ca]
gettype( ) works on variables, but the case we have is: if(strpos($whatWeWant, $typeSeperator) === FALSE) {
I don't know if it works on expressions and constants.
Anyway, looking at the code, we usually workaround this strpos problem with the "append a blank" trick:
if (strpos(' ' . $goto, 'tbl_properties') == 1) {
Marc
Of course, it does. gettype() checks the type of the expression. A variable is also an expression, just like a function call, a mathmatic operation or whatever. I'm taking your example and using my workaround: if (strpos($whatWeWant, $typeSeperator) == FALSE && gettype(strpos($whatWeWant, $typeSeperator)) == gettype(FALSE)) { Of course, we can make this a bit shorter: $tmp = strpos($whatWeWant, $typeSeperator); if (!$tmp && gettype($tmp) == 'boolean') { But our usual workaround for the strpos problem is this one: if (!strpos(' ' . $whatWeWant, $typeSeperator)) { Your code above appears incorrect to me because we want to have the case that the needle string does not appear in the haystack string, don't we? So 1 is wrong, it has to be 0 or FALSE (doesn't matter since 0 == FALSE :o) ). Alexander M. Turek <alex@bugfixes.info> +-----------------------------+ | The phpMyAdmin Project | | http://www.phpmyadmin.net | | rabus@users.sourceforge.net | +-----------------------------+ | [bugfixes.info] | | http://www.bugfixes.info | | rabus@bugfixes.info | +-----------------------------+